# What is the integral of sin?

## What is the integral of sin?

The integral of sinx is −cosx+C and the integral of cosx is sinx+C. …

What is the integration of Cscx?

We’ve found that the integral of cscx is -ln |cscx + cotx| + C.

Is arcsec equal to cos?

The functions are usually abbreviated: arcsine (arcsin), arccosine (arccos), arctangent (arctan) arccosecant (arccsc), arcsecant (arcsec), and arccotangent (arccot)….Math2.org Math Tables:

sin(q) = opp/hyp csc(q) = 1/sin(q)
cos(q) = adj/hyp sec(q) = 1/cos(q)
tan(q) = sin(q)/cos(q) cot(q) = 1/tan(q)

### What happens when you integrate sin?

Integrating sin(mt) and cos(mt) over a full period equals zero. Created by Sal Khan.

What is the integral of sin2x?

Answer: ∫sin2x dx = −½ cos(2x)+C Then, du = 2dx.

Why is the integral of Sinx 0?

Truong-Son N. Using the definition of the integral and the fact that sinx is an odd function, from 0 to 2π , with equal area under the curve at [0,π] and above the curve at [π,2π] , the integral is 0 .

## What is the Antiderivative of sin 2x?

Answer: The antiderivative of sin2 x is x/ 2 – (sinx cosx) / 2.

Is cot cos a sin?

Today we discuss the four other trigonometric functions: tangent, cotangent, secant, and cosecant. The tangent of x is defined to be its sine divided by its cosine: tan x = sin x cos x . The cotangent of x is defined to be the cosine of x divided by the sine of x: cot x = cos x sin x .

How to integrate arcsec ( x ), substitution and partial fractions?

Method: To integrate arcsec(x), substitution, then integrate by parts. You’ll also need ∫secudu, which can be done by substitution and partial fractions. Here’s a nice explanation: http://socratic.org/questions/what-is-the-integral-of-sec-x . Let y = arcsec(x), so x = secy and dx = secytanydy. With this substitution, the integral becomes:

### Are there integration formulas resulting in inverse trigonometric functions?

Rule: Integration Formulas Resulting in Inverse Trigonometric Functions The following integration formulas yield inverse trigonometric functions: Let y = arcsinx a. Then asiny = x. Now using implicit differentiation, we obtain dy dx = 1 acosy. For − π 2 ≤ y ≤ π 2, cosy ≥ 0.

Why are we reluctant to change the integrand of an integral?

It is common to be reluctant to manipulate the integrand of an integral; at first, our grasp of integration is tenuous and one may think that working with the integrand will improperly change the results.

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